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To calculate the work required to compress the spring from ?30? cm to ?25? cm, we pretend that the spring ends at the origin, which means that compressing it to ?25? cm means we’ve compressed it to ?-5?, because ?25-30=-5?.īut we need to convert the units from cm to m, so the interval becomes ?0? m to ?-0.05? m. The work done to stretch a spring with natural length ?30? cm and spring constant ?k=500? from ?42? cm to ?48? cm is ?4.5? J. Stretching it to ?48? cm means we’ve stretched it from the origin to ?18?, because ?48-30=18?.īut we need to convert the units from cm to m, so the interval becomes ?0.12? m to ?0.18? m.
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To calculate the work required to stretch the spring from ?42? cm to ?48? cm, we pretend that the spring at its natural length of ?30? cm ends at the origin, which means that stretching it to ?42? cm means we’ve stretched it to ?12?, because ?42-30=12?.
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With ?k?, we can develop a generic equation for our spring using Hooke’s Law. Remember that we’ll be finding work in terms of Newtons and meters, which is why we converted ?10? cm to ?0.10? m.
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Now that we know that k is the spring constant, we will look at the spring constant. The spring constant units are given as Newton per meter. Since we know that a ?50? N force is required to stretch and hold the spring at a length of ?40? cm, from its natural length of ?30? cm, we’ll set ?F(x)=50? and ?x=0.10? m, which is the difference between the natural length and the stretched length, converted from cm to m. Where F represents the restoring force of the spring, x is the displacement of the spring, and k is known as the spring constant. We’ll use Hooke’s Law to find ?F(x)?, but first we need to find ?k?. How much work is done to compress the spring from ?30? cm to ?25? cm? Substitute them into the formula: F -kx -80 0.15 12 N. Determine the displacement of the spring - let's say, 0.15 m.
#Spring physics calculator how to#
How much work is done to stretch the spring from ?42? cm to ?48? cm? How to use the Hooke's law calculator Choose a value of spring constant - for example, 80 N/m. A ?50? N force is required to stretch and hold the spring at a length of ?40? cm. The work done on the spring is actually the work by you and is k*x², and the work done by the spring is 1/2 kx² ( this is the actual energy you transfer to spring ) so this is the work energy produced in the spring.When you know natural length and the force required to stretch the springĪ spring has a natural length of ?30? cm. This is your answer where you have gone wrong. model of a variety of motions, such as the oscillation of a spring. a triangle ( remember area=force time deflection), and in that total work done by the spring is converted into potential energy which is stored in the spring itself while half of the triangle shows the resistive force which is resisting the work done by you in compression and half of the same force is actually energy to regain its shape. In mechanics and physics, simple harmonic motion is a type of periodic motion where the. Now, consider half of the square area I.e. (Note that sxy is not a calculator key, but its value may be. The Hookes Law Calculator uses the formula Fs -kx where F is the restoring force exerted by the spring, k is the spring constant and x is the displacement. force is directly proportional to deflection, where $k$ (stiffness) is constant, it will look like a square, in that at any point you can find the amount of force require to get desired displacement or deflection. , J in Maths and Physics tests A starting point would be to plot the marks as a. Let the force be $f$ and displacement be $d$, then when you draw a graph according to Hooke law (I.e. Actually the force which you are applying is not constant.